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FileUpload Application in Servlet

Posted on 26/11/2011 by Admin

Here We are going to see,How to create a FileUploadApplication using Java Zoom API

Directory Structure

upload1.html

<form action="uplurl" method="post" enctype="multipart/form-data">

Select File1 <input type="file" name="file1" />
Select File2 <input type="file" name="file2" />

<input type="Submit" value="Upload" />

</form>

web.xml

<web-app>

<servlet>
<servlet-name>uplsrv</servlet-name>
<servlet-class>UplSrv1</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>uplsrv</servlet-name>
<url-pattern>/uplurl</url-pattern>
</servlet-mapping>

</web-app>

UplSrv1.java

//UplSrv1.java
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import javazoom.upload.*;
import java.util.*;

public class UplSrv1 extends HttpServlet {
public void doPost(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
PrintWriter pw = res.getWriter();

try {

// set location for saving uploded files
UploadBean upb = new UploadBean();
upb.setFolderstore("c:/store");
upb.setOverwrite(false);

MultipartFormDataRequest nreq = new MultipartFormDataRequest(req);
upb.store(nreq); // completes files uploding

// display names of the uploded files
pw.println("The uploded files are  ");

Hashtable ht = nreq.getFiles();// gives all uploded files

Enumeration e = ht.elements();
while (e.hasMoreElements()) {
UploadFile file = (UploadFile) e.nextElement();
pw.println(file.getFileName() + " ");
}// while

}// try
catch (Exception e) {
pw.println(e);
}// catch
}// doPost ()
}// class

Jars required in classpath

servlet-api.jar
uploadbean.jar

Jars required in lib Folder
(See the directory structure)

Compile the ServletProgram

c:\JavaZoomUpload\WEB-INF\classes>javac *.java

Running the Application

Copy the JavaZoomUpload Application and paste it to web-apps folder of Tomcat

Executing the Application

Start tomcat server.and then give the following request from browser window

http://localhost:2012/JavaZoomUpload/upload1.html

You will get the screen

Select any two file,and click upload button.The file will be uploaded and stored in C:\store folder of the server.(in our case,It will be stored in our c:\store folder.

Upon successful upload,you will get the success screen

Hope,You like this tutorial.

Thank You